integral of 2x^4+3sqrt(x)+1/(x^3)

Lösung

\int 2 x^{4} + 3 x + \frac{1}{x ^{3}} d x

\frac{2 x ^{5}}{5} + 2 x^{\frac{3}{2}} - \frac{1}{2 x ^{2}} + C

Schritte zur Lösung

\int 2 x^{4} + 3 x + \frac{1}{x ^{3}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{4} d x + \int 3 x d x + \int \frac{1}{x ^{3}} d x

\int 2 x^{4} d x = \frac{2 x ^{5}}{5}

\int 3 x d x = 2 x^{\frac{3}{2}}

\int \frac{1}{x ^{3}} d x = - \frac{1}{2 x ^{2}}

= \frac{2 x ^{5}}{5} + 2 x^{\frac{3}{2}} - \frac{1}{2 x ^{2}}

Füge eine Konstante zur Lösung hinzu

= \frac{2 x ^{5}}{5} + 2 x^{\frac{3}{2}} - \frac{1}{2 x ^{2}} + C

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