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Frequently Asked Questions (FAQ)
What is the derivative of y=sqrt(x)+x^{3/2}-8x ?
- The derivative of y=sqrt(x)+x^{3/2}-8x is 1/(2x^{1/2)}+(3x^{1/2})/2-8
What is the first derivative of y=sqrt(x)+x^{3/2}-8x ?
- The first derivative of y=sqrt(x)+x^{3/2}-8x is 1/(2x^{1/2)}+(3x^{1/2})/2-8