What is the integral of t/(sqrt(t)) ?

The integral of t/(sqrt(t)) is 2/3 t^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of t/(sqrt(t))

\int \frac{t}{t} d t

\frac{2}{3} t^{\frac{3}{2}} + C

Solution steps

\int \frac{t}{t} d t

Simplify

\frac{t}{t} : t

= \int t d t

Apply the Power Rule

= \frac{2}{3} t^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} t^{\frac{3}{2}} + C

\int \frac{x ^{2} - x + 1}{x + 1} d x

in t e g r a l \frac{1}{2 ^{x}}

\int (cos^{5} (x)) d x

\int \frac{7 x ^{2} + x + 12}{3 x ^{3} + 12 x} d x

\int \frac{1 - x ^{2}}{x ^{2} ( 1 + x ^{2} )} d x

What is the integral of t/(sqrt(t)) ?
The integral of t/(sqrt(t)) is 2/3 t^{3/2}+C