What is the integral of 4sec^2(4x) ?

The integral of 4sec^2(4x) is tan(4x)+C

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integral of 4sec^2(4x)

\int 4 sec^{2} (4 x) d x

tan (4 x) + C

Solution steps

\int 4 sec^{2} (4 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int sec^{2} (4 x) d x

Apply u-substitution

= 4 \cdot \int sec^{2} (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{4} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= 4 \cdot \frac{1}{4} tan (u)

Substitute back

u = 4 x

= 4 \cdot \frac{1}{4} tan (4 x)

Simplify

4 \cdot \frac{1}{4} tan (4 x) : tan (4 x)

= tan (4 x)

Add a constant to the solution

= tan (4 x) + C

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