What is the integral of (-2)/(7x^4) ?

The integral of (-2)/(7x^4) is 2/(21x^3)+C

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integral of (-2)/(7x^4)

\int \frac{- 2}{7 x ^{4}} d x

\frac{2}{21 x ^{3}} + C

Solution steps

\int \frac{- 2}{7 x ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{- 2}{7} \cdot \int \frac{1}{x ^{4}} d x

Simplify

= (- \frac{2}{7}) \cdot \int \frac{1}{x ^{4}} d x

Apply the Power Rule

= (- \frac{2}{7}) (- \frac{1}{3 x ^{3}})

Simplify

(- \frac{2}{7}) (- \frac{1}{3 x ^{3}}) : \frac{2}{21 x ^{3}}

= \frac{2}{21 x ^{3}}

Add a constant to the solution

= \frac{2}{21 x ^{3}} + C

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What is the integral of (-2)/(7x^4) ?
The integral of (-2)/(7x^4) is 2/(21x^3)+C