What is the integral of-2sin(2x)sin(x) ?

The integral of-2sin(2x)sin(x) is -4/3 sin^3(x)+C

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integral of-2sin(2x)sin(x)

\int - 2 sin (2 x) sin (x) d x

- \frac{4}{3} sin^{3} (x) + C

Solution steps

\int - 2 sin (2 x) sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int sin (2 x) sin (x) d x

Rewrite using trig identities

= - 2 \cdot \int 2 sin^{2} (x) cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot 2 \cdot \int sin^{2} (x) cos (x) d x

Apply u-substitution

= - 2 \cdot 2 \cdot \int u^{2} d u

Apply the Power Rule

= - 2 \cdot 2 \cdot \frac{u ^{3}}{3}

Substitute back

u = sin (x)

= - 2 \cdot 2 \cdot \frac{sin ^{3} ( x )}{3}

Simplify

- 2 \cdot 2 \cdot \frac{sin ^{3} ( x )}{3} : - \frac{4}{3} sin^{3} (x)

= - \frac{4}{3} sin^{3} (x)

Add a constant to the solution

= - \frac{4}{3} sin^{3} (x) + C

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What is the integral of-2sin(2x)sin(x) ?
The integral of-2sin(2x)sin(x) is -4/3 sin^3(x)+C