What is the integral of sin^2(x)in(x) ?

The integral of sin^2(x)in(x) is d(-cos(x)+(cos^3(x))/3)+C

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integral of sin^2(x)in(x)

\int sin^{2} (x) d sin (x) d x

d (- cos (x) + \frac{cos ^{3} ( x )}{3}) + C

Solution steps

\int sin^{2} (x) d sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d \cdot \int sin^{2} (x) sin (x) d x

Rewrite using trig identities

= d \cdot \int (1 - cos^{2} (x)) sin (x) d x

Apply u-substitution

= d \cdot \int - 1 + u^{2} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= d (- \int 1 d u + \int u^{2} d u)

\int 1 d u = u

\int u^{2} d u = \frac{u ^{3}}{3}

= d (- u + \frac{u ^{3}}{3})

Substitute back

u = cos (x)

= d (- cos (x) + \frac{cos ^{3} ( x )}{3})

Add a constant to the solution

= d (- cos (x) + \frac{cos ^{3} ( x )}{3}) + C

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What is the integral of sin^2(x)in(x) ?
The integral of sin^2(x)in(x) is d(-cos(x)+(cos^3(x))/3)+C