integral of (5x^3+1)^4x^5

解

\int (5 x^{3} + 1)^{4} x^{5} d x

\frac{625 x ^{18}}{18} + \frac{100 x ^{15}}{3} + \frac{25 x ^{12}}{2} + \frac{20 x ^{9}}{9} + \frac{x ^{6}}{6} + C

解答ステップ

\int (5 x^{3} + 1)^{4} x^{5} d x

拡張

(5 x^{3} + 1)^{4} x^{5} : 625 x^{17} + 500 x^{14} + 150 x^{11} + 20 x^{8} + x^{5}

= \int 625 x^{17} + 500 x^{14} + 150 x^{11} + 20 x^{8} + x^{5} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 625 x^{17} d x + \int 500 x^{14} d x + \int 150 x^{11} d x + \int 20 x^{8} d x + \int x^{5} d x

\int 625 x^{17} d x = \frac{625 x ^{18}}{18}

\int 500 x^{14} d x = \frac{100 x ^{15}}{3}

\int 150 x^{11} d x = \frac{25 x ^{12}}{2}

\int 20 x^{8} d x = \frac{20 x ^{9}}{9}

\int x^{5} d x = \frac{x ^{6}}{6}

= \frac{625 x ^{18}}{18} + \frac{100 x ^{15}}{3} + \frac{25 x ^{12}}{2} + \frac{20 x ^{9}}{9} + \frac{x ^{6}}{6}

定数を解答に追加する

= \frac{625 x ^{18}}{18} + \frac{100 x ^{15}}{3} + \frac{25 x ^{12}}{2} + \frac{20 x ^{9}}{9} + \frac{x ^{6}}{6} + C