What is the derivative of 27n+3q^2n ?

The derivative of 27n+3q^2n is 6nq

What is the first derivative of 27n+3q^2n ?

The first derivative of 27n+3q^2n is 6nq

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derivative of

27 n + 3 q^{2} n

6 n q

Solution steps

\frac{d}{d q} (27 n + 3 q^{2} n)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d q} (27 n) + \frac{d}{d q} (3 q^{2} n)

\frac{d}{d q} (27 n) = 0

\frac{d}{d q} (3 q^{2} n) = 6 n q

= 0 + 6 n q

Simplify

= 6 n q

d er i v a t i v e y = \frac{4 x - 1}{2 x + 5}

\frac{d}{d x} (sin (x^{3}) cos (x^{2}))

\frac{d y}{d x} = x^{2} - y - 2, y (0) = - 1

\int_{0}^{5} 9800 π (5 - y) d y

\int (sin (x) cos^{3} (x)) d x

What is the derivative of 27n+3q^2n ?
The derivative of 27n+3q^2n is 6nq
What is the first derivative of 27n+3q^2n ?
The first derivative of 27n+3q^2n is 6nq