What is the integral of \sqrt[4]{x^4} ?

The integral of \sqrt[4]{x^4} is (x^2)/2+C

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integral of \sqrt[4]{x^4}

\int 4 x^{4} d x

\frac{x ^{2}}{2} + C

Solution steps

\int 4 x^{4} d x

4 x^{4} = (x),

assuming

x \geq 0

= \int x d x

Apply the Power Rule

= \frac{x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{2}}{2} + C

\int \frac{2 x + 3}{x ( x - 1 )} d x

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\int x^{2} \cdot x + 1 d x

What is the integral of \sqrt[4]{x^4} ?
The integral of \sqrt[4]{x^4} is (x^2)/2+C