What is the integral of (y-e^xz^2) ?

The integral of (y-e^xz^2) is yx-z^2e^x+C

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integral of (y-e^xz^2)

\int (y - e^{x} z^{2}) d x

y x - z^{2} e^{x} + C

Solution steps

\int y - e^{x} z^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int y d x - \int z^{2} e^{x} d x

\int y d x = y x

\int z^{2} e^{x} d x = z^{2} e^{x}

= y x - z^{2} e^{x}

Add a constant to the solution

= y x - z^{2} e^{x} + C

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