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Frequently Asked Questions (FAQ)
What is the derivative of 0.01(0.2x^2+4x+64^{2/3}) ?
- The derivative of 0.01(0.2x^2+4x+64^{2/3}) is (0.00666…(0.4x+4))/((0.2x^2+4x+64)^{1/3)}
What is the first derivative of 0.01(0.2x^2+4x+64^{2/3}) ?
- The first derivative of 0.01(0.2x^2+4x+64^{2/3}) is (0.00666…(0.4x+4))/((0.2x^2+4x+64)^{1/3)}