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Beliebt Rechnen >

4y^{''}-16y^'+19y=0

Lösung

4 y^{^{''}} - 16 y^{^{'}} + 19 y = 0

Lösung

y = e^{2 t} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2}))

Schritte zur Lösung

4 y^{''} (t) - 16 y^{'} (t) + 19 y = 0

Solve linear ODE:

y = e^{2 t} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2}))

y = e^{2 t} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2}))

Graph

Beliebte Beispiele

derivative of 2x^2cos(x)

\frac{d}{d x} (2 x^{2} cos (x))

\frac{y ^{^{'}}}{y} = x

tangent (6x)/(2+x^2)

t an g e n t \frac{6 x}{2 + x ^{2}}

(\partial)/(\partial y)(e^{2y}sin(-2x))

\frac{\partial}{\partial y} (e^{2 y} sin (- 2 x))

derivative f(x)=(2x+3)^{11}(4-5x)^9

d er i v a t i v e f (x) = (2 x + 3)^{11} (4 - 5 x)^{9}