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人気のある微分積分 >

integral of sqrt(x^2-5x+6)

解

\int x^{2} - 5 x + 6 d x

解

\frac{1}{8} (4 x x^{2} - 5 x + 6 - 10 x^{2} - 5 x + 6 - ln 2 x - 5 + 2 x^{2} - 5 x + 6) + C

解答ステップ

\int x^{2} - 5 x + 6 d x

平方完成する

x^{2} - 5 x + 6 : (x - \frac{5}{2})^{2} - \frac{1}{4}

= \int (x - \frac{5}{2})^{2} - \frac{1}{4} d x

u置換積分法を適用する

= \int \frac{4 u ^{2} - 1}{2} d u

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int 4 u^{2} - 1 d u

三角関数による置換を適用する

= \frac{1}{2} \cdot \int \frac{1}{2} tan^{2} (v) sec (v) d v

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \frac{1}{2} \cdot \int tan^{2} (v) sec (v) d v

三角関数の公式を使用して書き換える

= \frac{1}{2} \cdot \frac{1}{2} \cdot \int (- 1 + sec^{2} (v)) sec (v) d v

拡張

(- 1 + sec^{2} (v)) sec (v) : - sec (v) + sec^{3} (v)

= \frac{1}{2} \cdot \frac{1}{2} \cdot \int - sec (v) + sec^{3} (v) d v

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} \cdot \frac{1}{2} (- \int sec (v) d v + \int sec^{3} (v) d v)

\int sec (v) d v = ln ∣ tan (v) + sec (v) ∣

\int sec^{3} (v) d v = \frac{1}{2} sec (v) tan (v) + \frac{1}{2} ln ∣ tan (v) + sec (v) ∣

= \frac{1}{2} \cdot \frac{1}{2} (- ln ∣ tan (v) + sec (v) ∣ + \frac{1}{2} sec (v) tan (v) + \frac{1}{2} ln ∣ tan (v) + sec (v) ∣)

代用を戻す

= \frac{1}{2} \cdot \frac{1}{2} (- ln tan (arcsec (2 (x - \frac{5}{2}))) + sec (arcsec (2 (x - \frac{5}{2}))) + \frac{1}{2} sec (arcsec (2 (x - \frac{5}{2}))) tan (arcsec (2 (x - \frac{5}{2}))) + \frac{1}{2} ln tan (arcsec (2 (x - \frac{5}{2}))) + sec (arcsec (2 (x - \frac{5}{2}))))

簡素化

\frac{1}{2} \cdot \frac{1}{2} (- ln tan (arcsec (2 (x - \frac{5}{2}))) + sec (arcsec (2 (x - \frac{5}{2}))) + \frac{1}{2} sec (arcsec (2 (x - \frac{5}{2}))) tan (arcsec (2 (x - \frac{5}{2}))) + \frac{1}{2} ln tan (arcsec (2 (x - \frac{5}{2}))) + sec (arcsec (2 (x - \frac{5}{2})))) : \frac{1}{8} (4 x x^{2} - 5 x + 6 - 10 x^{2} - 5 x + 6 - ln 2 x - 5 + 2 x^{2} - 5 x + 6)

= \frac{1}{8} (4 x x^{2} - 5 x + 6 - 10 x^{2} - 5 x + 6 - ln 2 x - 5 + 2 x^{2} - 5 x + 6)

定数を解答に追加する

= \frac{1}{8} (4 x x^{2} - 5 x + 6 - 10 x^{2} - 5 x + 6 - ln 2 x - 5 + 2 x^{2} - 5 x + 6) + C

グラフ

人気の例

integral of ((2x+1))/(2x)

\int \frac{( 2 x + 1 )}{2 x} d x

integral of 1/((1-4x)^{3/2)}

\int \frac{1}{( 1 - 4 x ) ^{\frac{3}{2}}} d x

integral of x(2x-1)^{1/2}

\int x (2 x - 1)^{\frac{1}{2}} d x

integral of sqrt(16x^2+32)

\int 16 x^{2} + 32 d x

integral of 2/(2-x)

\int \frac{2}{2 - x} d x