What is the integral of 4csc^2(2x)cot(2x) ?

The integral of 4csc^2(2x)cot(2x) is -cot^2(2x)+C

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integral of 4csc^2(2x)cot(2x)

\int 4 csc^{2} (2 x) cot (2 x) d x

- cot^{2} (2 x) + C

Solution steps

\int 4 csc^{2} (2 x) cot (2 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int csc^{2} (2 x) cot (2 x) d x

Apply u-substitution

= 4 \cdot \int - \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 (- \frac{1}{2} \cdot \int u d u)

Apply the Power Rule

= 4 (- \frac{1}{2} \cdot \frac{u ^{2}}{2})

Substitute back

u = cot (2 x)

= 4 (- \frac{1}{2} \cdot \frac{cot ^{2} ( 2 x )}{2})

Simplify

4 (- \frac{1}{2} \cdot \frac{cot ^{2} ( 2 x )}{2}) : - cot^{2} (2 x)

= - cot^{2} (2 x)

Add a constant to the solution

= - cot^{2} (2 x) + C

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What is the integral of 4csc^2(2x)cot(2x) ?
The integral of 4csc^2(2x)cot(2x) is -cot^2(2x)+C