integral of (x+1)/((x^2+1)^2)

Lösung

\int \frac{x + 1}{( x ^{2} + 1 ) ^{2}} d x

\frac{x}{2 ( x ^{2} + 1 )} + \frac{1}{2} arctan (x) - \frac{1}{2 ( x ^{2} + 1 )} + C

Schritte zur Lösung

\int \frac{x + 1}{( x ^{2} + 1 ) ^{2}} d x

Wende die partielle Integration an

= \frac{1}{2} (x + 1) (arctan (x) + \frac{x}{1 + x ^{2}}) - \int \frac{1}{2} (arctan (x) + \frac{x}{1 + x ^{2}}) d x

\int \frac{1}{2} (arctan (x) + \frac{x}{1 + x ^{2}}) d x = \frac{1}{2} (x (arctan (x) + \frac{x}{1 + x ^{2}}) + \frac{1}{x ^{2} + 1})

= \frac{1}{2} (x + 1) (arctan (x) + \frac{x}{1 + x ^{2}}) - \frac{1}{2} (x (arctan (x) + \frac{x}{1 + x ^{2}}) + \frac{1}{x ^{2} + 1})

Vereinfache

\frac{1}{2} (x + 1) (arctan (x) + \frac{x}{1 + x ^{2}}) - \frac{1}{2} (x (arctan (x) + \frac{x}{1 + x ^{2}}) + \frac{1}{x ^{2} + 1}) : \frac{x}{2 ( x ^{2} + 1 )} + \frac{1}{2} arctan (x) - \frac{1}{2 ( x ^{2} + 1 )}

= \frac{x}{2 ( x ^{2} + 1 )} + \frac{1}{2} arctan (x) - \frac{1}{2 ( x ^{2} + 1 )}

Füge eine Konstante zur Lösung hinzu

= \frac{x}{2 ( x ^{2} + 1 )} + \frac{1}{2} arctan (x) - \frac{1}{2 ( x ^{2} + 1 )} + C

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