derivative f(t)=t^9sin(t)

Lösung

ableitung von

f (t) = t^{9} sin (t)

9 t^{8} sin (t) + cos (t) t^{9}

Schritte zur Lösung

\frac{d}{d t} (t^{9} sin (t))

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t^{9}, g = sin (t)

= \frac{d}{d t} (t^{9}) sin (t) + \frac{d}{d t} (sin (t)) t^{9}

\frac{d}{d t} (t^{9}) = 9 t^{8}

\frac{d}{d t} (sin (t)) = cos (t)

= 9 t^{8} sin (t) + cos (t) t^{9}

\int_{1}^{e} 4 x^{3} ln (x) d x

d er i v a t i v e - \frac{1}{2} x

\frac{\partial}{\partial x} (x^{3} e^{x})

n = 0 \sum \infty \frac{9 ^{n}}{n !}

\int \frac{3}{2} e^{- x} cos (2 x) d x