derivative 1/(x+4)

解答

导数

\frac{1}{x + 4}

- \frac{1}{( x + 4 ) ^{2}}

求解步骤

\frac{d}{d x} (\frac{1}{x + 4})

使用指数法则:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 4)^{- 1})

使用连锁律:

- \frac{1}{( x + 4 ) ^{2}} \frac{d}{d x} (x + 4)

= - \frac{1}{( x + 4 ) ^{2}} \frac{d}{d x} (x + 4)

\frac{d}{d x} (x + 4) = 1

= - \frac{1}{( x + 4 ) ^{2}} \cdot 1

化简

= - \frac{1}{( x + 4 ) ^{2}}

\int \frac{20}{( x - 1 ) ( x ^{2} + 9 )} d x

\frac{d}{d x} (\frac{2}{x ^{2} + 1})

d er i v a t i v e (x^{2} + 2 x) (1 - e^{x})

d er i v a t i v e 8 x + x

\frac{d}{d x} (\frac{4 x ^{5} + 7}{x ^{3}})