What is the first derivative of 2x^2+3 ?

The first derivative of 2x^2+3 is 4x

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derivative of 2x^2+3

derivative of

2 x^{2} + 3

4 x

Solution steps

\frac{d}{d x} (2 x^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3) = 0

= 4 x + 0

Simplify

= 4 x

\int (e^{7 x}) d x

x \to 0 + lim (2 x)

d er i v a t i v e f (x) = \frac{1 - x e ^{x}}{x + e ^{x}}

k = 1 \sum \infty (- 1)^{k}

x \to 1 lim (\frac{x ^{7} - 1}{x - 1})