derivative f(x)=2ln(6+x)

解答

导数

f (x) = 2 ln (6 + x)

\frac{2}{6 + x}

求解步骤

\frac{d}{d x} (2 ln (6 + x))

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (ln (6 + x))

使用连锁律:

\frac{1}{6 + x} \frac{d}{d x} (6 + x)

= \frac{1}{6 + x} \frac{d}{d x} (6 + x)

\frac{d}{d x} (6 + x) = 1

= 2 \cdot \frac{1}{6 + x} \cdot 1

化简

2 \cdot \frac{1}{6 + x} \cdot 1 : \frac{2}{6 + x}

= \frac{2}{6 + x}

\frac{d}{d x} (\frac{3}{lo g _{8} ( x )})

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