What is the solution for 8(dy)/(dx)+7e^{x+y}=0 ?

The solution for 8(dy)/(dx)+7e^{x+y}=0 is y=-ln((7e^x-c_{1})/8)

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8(dy)/(dx)+7e^{x+y}=0

8 \frac{d y}{d x} + 7 e^{x + y} = 0

y = - ln (\frac{7 e ^{x} - c _{1}}{8})

Solution steps

8 \frac{d y}{d x} + 7 e^{x + y} = 0

Solve separable ODE:

y = - ln (\frac{7 e ^{x} - c _{1}}{8})

y = - ln (\frac{7 e ^{x} - c _{1}}{8})

y^{^{'}} = t y

(t^{2} + 1) f^{^{'}} (t) + [f (t)]^{2} + 1 = 0

\frac{d}{d a} (cos (3 a) cos (2 a) + sin (4 a) sin (a))

\int_{0}^{9} x^{2} 81 - x^{2} d x

\int_{0.1}^{x} x d x

What is the solution for 8(dy)/(dx)+7e^{x+y}=0 ?
The solution for 8(dy)/(dx)+7e^{x+y}=0 is y=-ln((7e^x-c_{1})/8)