What is (d^2)/(dx^2)(ln(1+e^x)) ?

The answer to (d^2)/(dx^2)(ln(1+e^x)) is (e^x)/((1+e^x)^2)

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(d^2)/(dx^2)(ln(1+e^x))

\frac{d ^{2}}{d x ^{2}} (ln (1 + e^{x}))

\frac{e ^{x}}{( 1 + e ^{x} ) ^{2}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (ln (1 + e^{x}))

\frac{d}{d x} (ln (1 + e^{x})) = \frac{e ^{x}}{1 + e ^{x}}

= \frac{d}{d x} (\frac{e ^{x}}{1 + e ^{x}})

\frac{d}{d x} (\frac{e ^{x}}{1 + e ^{x}}) = \frac{e ^{x}}{( 1 + e ^{x} ) ^{2}}

= \frac{e ^{x}}{( 1 + e ^{x} ) ^{2}}

\frac{d}{d x} (\frac{e ^{x}}{x})

x \to 0 + lim (arcsin (2 x - 1))

im pl i c i t \frac{d y}{d x}, 3 x^{3} y = 6

d er i v a t i v e f (x) = - \frac{1}{4} x^{4} + \frac{27}{2} x^{2}

\int \frac{m ^{2}}{m + 1} d m

What is (d^2)/(dx^2)(ln(1+e^x)) ?
The answer to (d^2)/(dx^2)(ln(1+e^x)) is (e^x)/((1+e^x)^2)