derivative f(x)=((x^3+9))/(x^3)

Lösung

ableitung von

f (x) = \frac{( x ^{3} + 9 )}{x ^{3}}

- \frac{27}{x ^{4}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{3} + 9}{x ^{3}})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{3} + 9 ) x ^{3} - \frac{d}{d x} ( x ^{3} ) ( x ^{3} + 9 )}{( x ^{3} ) ^{2}}

\frac{d}{d x} (x^{3} + 9) = 3 x^{2}

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{3 x ^{2} x ^{3} - 3 x ^{2} ( x ^{3} + 9 )}{( x ^{3} ) ^{2}}

Vereinfache

\frac{3 x ^{2} x ^{3} - 3 x ^{2} ( x ^{3} + 9 )}{( x ^{3} ) ^{2}} : - \frac{27}{x ^{4}}

= - \frac{27}{x ^{4}}

x \to 0 lim (tan (3 x))

\int \frac{x - 2}{x} d x

d er i v a t i v e y = - 2 e^{- x^{2}} x

\int \frac{3 x}{1 + x ^{3}} d x

y^{^{'}} + 2 x y = y + 4 x - 2