What is the solution for y^'+1/(200+3t)y=12 ?

The solution for y^'+1/(200+3t)y=12 is y=3(3t+200)+(c_{1})/(\sqrt[3]{200+3t)}

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y^'+1/(200+3t)y=12

y^{^{'}} + \frac{1}{200 + 3 t} y = 12

y = 3 (3 t + 200) + \frac{c _{1}}{3 200 + 3 t}

Solution steps

y^{'} (t) + \frac{1}{200 + 3 t} y = 12

Solve linear ODE:

y = 3 (3 t + 200) + \frac{c _{1}}{3 200 + 3 t}

y = 3 (3 t + 200) + \frac{c _{1}}{3 200 + 3 t}

x \to 0 lim (ln (1 - 9 x))

\frac{d}{d x} (1 - x^{6})

d er i v a t i v e arctan (2 y)

\frac{\partial}{\partial x} (arctan (x - 2 y))

y^{^{''}} - a y = 0

What is the solution for y^'+1/(200+3t)y=12 ?
The solution for y^'+1/(200+3t)y=12 is y=3(3t+200)+(c_{1})/(\sqrt[3]{200+3t)}