What is the solution for y^{''}+80y^'+1200y=0 ?

The solution for y^{''}+80y^'+1200y=0 is y=c_{1}e^{-20t}+c_{2}e^{-60t}

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y^{''}+80y^'+1200y=0

y^{^{''}} + 80 y^{^{'}} + 1200 y = 0

y = c_{1} e^{- 20 t} + c_{2} e^{- 60 t}

Solution steps

y^{''} (t) + 80 y^{'} (t) + 1200 y = 0

Solve linear ODE:

y = c_{1} e^{- 20 t} + c_{2} e^{- 60 t}

y = c_{1} e^{- 20 t} + c_{2} e^{- 60 t}

\int 2 x (4 x - 3)^{3} d x

d er i v a t i v e \frac{2}{( 3 x ^{2} + 7 ) ^{2}}

s l o p e f (x) = 9 x

\int (sin (x))^{3} d x

\frac{\partial}{\partial r} (r)

What is the solution for y^{''}+80y^'+1200y=0 ?
The solution for y^{''}+80y^'+1200y=0 is y=c_{1}e^{-20t}+c_{2}e^{-60t}