What is the solution for (dy)/(dt)= 9/40-y/(200) ?

The solution for (dy)/(dt)= 9/40-y/(200) is y=-e^{(-t-c_{1})/(200)}+45

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(dy)/(dt)= 9/40-y/(200)

\frac{d y}{d t} = \frac{9}{40} - \frac{y}{200}

y = - e^{\frac{- t - c _{1}}{200}} + 45

Solution steps

\frac{d y}{d t} = \frac{9}{40} - \frac{y}{200}

Solve separable ODE:

y = - e^{\frac{- t - c _{1}}{200}} + 45

y = - e^{\frac{- t - c _{1}}{200}} + 45

t a y l or x^{\frac{11}{2}}, 5

\frac{d}{d x} (5 x^{2} e^{3 x - 7})

\frac{d y}{d x} + \frac{3}{x} y = 16 y^{3}

\int_{4}^{7} \frac{x}{x ^{2} + 6 x + 13} d x

t an g e n t f (x) = 2 x^{2} + 2 x, at x = - 3

What is the solution for (dy)/(dt)= 9/40-y/(200) ?
The solution for (dy)/(dt)= 9/40-y/(200) is y=-e^{(-t-c_{1})/(200)}+45