What is the derivative of (3x^2+2x-1^4) ?

The derivative of (3x^2+2x-1^4) is 4(3x^2+2x-1)^3(6x+2)

What is the first derivative of (3x^2+2x-1^4) ?

The first derivative of (3x^2+2x-1^4) is 4(3x^2+2x-1)^3(6x+2)

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\frac{d}{d x} ((3 x^{2} + 2 x - 1)^{4})

4 (3 x^{2} + 2 x - 1)^{3} (6 x + 2)

Solution steps

\frac{d}{d x} ((3 x^{2} + 2 x - 1)^{4})

Apply the chain rule:

4 (3 x^{2} + 2 x - 1)^{3} \frac{d}{d x} (3 x^{2} + 2 x - 1)

= 4 (3 x^{2} + 2 x - 1)^{3} \frac{d}{d x} (3 x^{2} + 2 x - 1)

\frac{d}{d x} (3 x^{2} + 2 x - 1) = 6 x + 2

= 4 (3 x^{2} + 2 x - 1)^{3} (6 x + 2)

\frac{d y}{d t} = (y^{2} + 1) t

\frac{d}{d x} (10 + x)

x \to 0 lim (\frac{2}{x} - \frac{2}{x ^{2} - x})

\frac{\partial}{\partial x} (x y^{2} z^{2})

\int (\frac{1}{4} x^{6} - 5 x^{3} + 9 x) d x

What is the derivative of (3x^2+2x-1^4) ?
The derivative of (3x^2+2x-1^4) is 4(3x^2+2x-1)^3(6x+2)
What is the first derivative of (3x^2+2x-1^4) ?
The first derivative of (3x^2+2x-1^4) is 4(3x^2+2x-1)^3(6x+2)