What is the integral from-infinity to 0 of e^{-|x|} ?

The integral from-infinity to 0 of e^{-|x|} is 1

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integral from-infinity to 0 of e^{-|x|}

\int_{- \infty}^{0} e^{- ∣ x ∣} d x

1

Solution steps

\int_{- \infty}^{0} e^{- ∣ x ∣} d x

Eliminate Absolutes

= \int_{- \infty}^{0} e^{- (- x)} d x

Compute the indefinite integral:

\int e^{- (- x)} d x = e^{x} + C

Compute the boundaries:

\int_{- \infty}^{0} e^{- (- x)} d x = 1 - 0

= 1 - 0

Simplify

= 1

y^{^{''}} + 2 y^{^{'}} + y = x^{- 6} e^{- x}

\int \frac{x + 2}{x ^{2} + 3 x - 4} d x

s l o p e (2) (- 3.1)

\frac{d x}{d t} = sin (2 π (t + 3)), x (3) = 1

t an g e n t y = 2 x^{2}, (6, 10)

What is the integral from-infinity to 0 of e^{-|x|} ?
The integral from-infinity to 0 of e^{-|x|} is 1