What is (\partial)/(\partial x)(4pi^2 x/(y^2)) ?

The answer to (\partial)/(\partial x)(4pi^2 x/(y^2)) is (4pi^2)/(y^2)

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(\partial)/(\partial x)(4pi^2 x/(y^2))

\frac{\partial}{\partial x} (4 π^{2} \frac{x}{y ^{2}})

\frac{4 π ^{2}}{y ^{2}}

Solution steps

\frac{\partial}{\partial x} (4 π^{2} \frac{x}{y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 π^{2} \frac{1}{y ^{2}} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 4 π^{2} \frac{1}{y ^{2}} \cdot 1

Simplify

4 π^{2} \frac{1}{y ^{2}} \cdot 1 : \frac{4 π ^{2}}{y ^{2}}

= \frac{4 π ^{2}}{y ^{2}}

\int \frac{1}{1 - 25 x ^{2}} d x

\frac{d}{d x} (\frac{- 5}{4 x ^{3}})

in v erse l a pl a ce \frac{5 s + 5}{s ( s ^{2} + 6 s + 10 )}

x \to - 1 lim (- \frac{2}{( x + 1 ) ^{2}})

\frac{d}{d y} (x - y)

What is (\partial)/(\partial x)(4pi^2 x/(y^2)) ?
The answer to (\partial)/(\partial x)(4pi^2 x/(y^2)) is (4pi^2)/(y^2)