What is the tangent of 3x^2-5x+2 ?

The tangent of 3x^2-5x+2 is y=(6a_{0}-5)x-3a_{0}^2+2

tangent of 3x^2-5x+2

tangent of

3 x^{2} - 5 x + 2

y = (6 a_{0} - 5) x - 3 a_{0}^{2} + 2

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} - 5 a_{0} + 2)

Find the slope of

y = 3 x^{2} - 5 x + 2 : \frac{d y}{d x} = 6 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6 a_{0} - 5

Find the line with slope m=

6 a_{0} - 5

and passing through

(a_{0}, 3 a_{0}^{2} - 5 a_{0} + 2) : y = (6 a_{0} - 5) x - 3 a_{0}^{2} + 2

y = (6 a_{0} - 5) x - 3 a_{0}^{2} + 2

\frac{d}{d x} (\frac{x ^{2} + 5 x - 1}{x ^{2}})

d er i v a t i v e - 3 + 12 x - 3 x^{2}

s l o p e in t erce pt - 6 x = 10 - y - 36 x = 48 - 6 y

\int 4 cos^{2} (x) tan^{3} (x) d x

y^{^{''}} - 6 y^{^{'}} + 9 y = e^{3 x} ln (x)

What is the tangent of 3x^2-5x+2 ?
The tangent of 3x^2-5x+2 is y=(6a_{0}-5)x-3a_{0}^2+2