What is the tangent of 5x-2sqrt(x) ?

The tangent of 5x-2sqrt(x) is y=(5-1/(sqrt(a_{0))})x-sqrt(a_{0)}

tangent of 5x-2sqrt(x)

tangent of

5 x - 2 x

y = (5 - \frac{1}{a _{0}}) x - a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 5 a_{0} - 2 a_{0})

Find the slope of

y = 5 x - 2 x : \frac{d y}{d x} = 5 - \frac{1}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5 - \frac{1}{a _{0}}

Find the line with slope m=

5 - \frac{1}{a _{0}}

and passing through

(a_{0}, 5 a_{0} - 2 a_{0}) : y = (5 - \frac{1}{a _{0}}) x - a_{0}

y = (5 - \frac{1}{a _{0}}) x - a_{0}

y^{^{'}} = 5 y sin (4 x), y (\frac{π}{8}) = 3

n = 1 \sum \infty \frac{1}{π ^{n}}

x \to 0 lim (x (\frac{1}{2 x}))

t a y l or (x - 4)^{n}, 4

a re a y = cos (x), y = 1 - cos (x), 0 \leq x \leq π

What is the tangent of 5x-2sqrt(x) ?
The tangent of 5x-2sqrt(x) is y=(5-1/(sqrt(a_{0))})x-sqrt(a_{0)}