What is the derivative of-5sin(5x) ?

The derivative of-5sin(5x) is -25cos(5x)

What is the first derivative of-5sin(5x) ?

The first derivative of-5sin(5x) is -25cos(5x)

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\frac{d}{d x} (- 5 sin (5 x))

- 25 cos (5 x)

Solution steps

\frac{d}{d x} (- 5 sin (5 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 \frac{d}{d x} (sin (5 x))

Apply the chain rule:

cos (5 x) \frac{d}{d x} (5 x)

= cos (5 x) \frac{d}{d x} (5 x)

\frac{d}{d x} (5 x) = 5

= - 5 cos (5 x) \cdot 5

Simplify

= - 25 cos (5 x)

\int \frac{1}{u 1 + u ^{2}} d u

\frac{d}{d x} (7 sin (337 x + \frac{7 π}{18}))

\int \frac{2 x + 6}{x ^{2} + 2 x + 5} d x

p a r t ia l f r a c t i o n \frac{x ^{2}}{1 - x ^{2}}

(y^{3} - 1) e^{x} + 3 y^{2} (e^{x} + 1) \frac{d y}{d x} = 0, y (0) = 2

What is the derivative of-5sin(5x) ?
The derivative of-5sin(5x) is -25cos(5x)
What is the first derivative of-5sin(5x) ?
The first derivative of-5sin(5x) is -25cos(5x)