What is the tangent of f(x)=4e^xcos(x),\at x=0 ?

The tangent of f(x)=4e^xcos(x),\at x=0 is y=4x+4

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tangent of f(x)=4e^xcos(x),\at x=0

tangent of

f (x) = 4 e^{x} cos (x), at x = 0

y = 4 x + 4

Solution steps

Find the tangent point:

(0, 4)

Find the slope of

f (x) = 4 e^{x} cos (x) : \frac{df ( x )}{d x} = 4 (e^{x} cos (x) - e^{x} sin (x))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(0, 4) : y = 4 x + 4

y = 4 x + 4

d er i v a t i v e y = \frac{5 x ^{2} + 4}{x + 3}

\int \frac{tan ( x ) + 1}{cos ^{2} ( x )} d x

\int \frac{3 x ^{2}}{x ^{3} + 8} d x

\int (- 8 cos (- 2)) ddd

\int 3 cos (7 x) d x

What is the tangent of f(x)=4e^xcos(x),\at x=0 ?
The tangent of f(x)=4e^xcos(x),\at x=0 is y=4x+4