What is the solution for (df)/(dx)f(x)=cos(2x) ?

The solution for (df)/(dx)f(x)=cos(2x) is f(x)=sqrt(sin(2x)+c_{1)},f(x)=-sqrt(sin(2x)+c_{1)}

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(df)/(dx)f(x)=cos(2x)

\frac{df}{d x} f (x) = cos (2 x)

f (x) = sin (2 x) + c_{1}, f (x) = - sin (2 x) + c_{1}

Solution steps

\frac{df}{d x} f = cos (2 x)

Solve separable ODE:

f (x) = sin (2 x) + c_{1}, f (x) = - sin (2 x) + c_{1}

f (x) = sin (2 x) + c_{1}, f (x) = - sin (2 x) + c_{1}

(cos (7 x)) y^{^{'}} - 7 (tan (7 x)) y = 9 sec (7 x)

\int_{1}^{2} \frac{3}{x ^{4}} d x

\frac{d r}{d θ} = \frac{r ^{2} + 4 r θ}{2 θ ^{2}}

d er i v a t i v e sin (3 x^{2} + 2)

\frac{d}{d z} (\frac{1}{z ^{2}})

What is the solution for (df)/(dx)f(x)=cos(2x) ?
The solution for (df)/(dx)f(x)=cos(2x) is f(x)=sqrt(sin(2x)+c_{1)},f(x)=-sqrt(sin(2x)+c_{1)}