What is area tan(3x),2sin(3x),-pi/9 , pi/9 ?

The answer to area tan(3x),2sin(3x),-pi/9 , pi/9 is (-2ln(2)+2)/3

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area tan(3x),2sin(3x),-pi/9 , pi/9

area

tan (3 x), 2 sin (3 x), - \frac{π}{9}, \frac{π}{9}

\frac{- 2 ln ( 2 ) + 2}{3}

Decimal

0.20456 \dots

Solution steps

Apply the area formula:

\int_{- \frac{π}{9}}^{\frac{π}{9}} ∣ tan (3 x) - 2 sin (3 x) ∣ d x

Solve

\int_{- \frac{π}{9}}^{\frac{π}{9}} ∣ tan (3 x) - 2 sin (3 x) ∣ d x : \frac{- 2 ln ( 2 ) + 2}{3}

The area is:

= \frac{- 2 ln ( 2 ) + 2}{3}

d er i v a t i v e 4 sec^{2} (x)

\int sec^{2} (θ) - 1 d θ

\int e^{x} - \frac{2}{x} d x

\int_{- 3}^{0} (x^{2} - 4 x + 7) d x

\int (x + 3) 2 - x d x

What is area tan(3x),2sin(3x),-pi/9 , pi/9 ?
The answer to area tan(3x),2sin(3x),-pi/9 , pi/9 is (-2ln(2)+2)/3