What is the solution for (dy)/(dt)+3y+e^t+3=0 ?

The solution for (dy)/(dt)+3y+e^t+3=0 is y=-(e^t)/4-1+(c_{1})/(e^{3t)}

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(dy)/(dt)+3y+e^t+3=0

\frac{d y}{d t} + 3 y + e^{t} + 3 = 0

y = - \frac{e ^{t}}{4} - 1 + \frac{c _{1}}{e ^{3 t}}

Solution steps

\frac{d y}{d t} + 3 y + e^{t} + 3 = 0

Solve linear ODE:

y = - \frac{e ^{t}}{4} - 1 + \frac{c _{1}}{e ^{3 t}}

y = - \frac{e ^{t}}{4} - 1 + \frac{c _{1}}{e ^{3 t}}

\int (6 sec^{2} (x)) d x

x^{3} + 3 y - x \frac{d y}{d x} = 0

\frac{d}{d x} (e^{a r c t a n (x)})

\int \frac{1}{x ( y + 1 )} d y

x \to 10 lim (\frac{x ^{2} - 99}{x - 10})

What is the solution for (dy)/(dt)+3y+e^t+3=0 ?
The solution for (dy)/(dt)+3y+e^t+3=0 is y=-(e^t)/4-1+(c_{1})/(e^{3t)}