What is the integral of e^xx^{-2} ?

The integral of e^xx^{-2} is -(e^x)/x+\Ei(x)+C

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integral of e^xx^{-2}

\int e^{x} x^{- 2} d x

- \frac{e ^{x}}{x} + Ei (x) + C

Solution steps

\int e^{x} x^{- 2} d x

Simplify

e^{x} x^{- 2} : \frac{e ^{x}}{x ^{2}}

= \int \frac{e ^{x}}{x ^{2}} d x

Apply Integration By Parts

= - \frac{e ^{x}}{x} - \int - \frac{e ^{x}}{x} d x

\int - \frac{e ^{x}}{x} d x = - Ei (x)

= - \frac{e ^{x}}{x} - (- Ei (x))

Simplify

= - \frac{e ^{x}}{x} + Ei (x)

Add a constant to the solution

= - \frac{e ^{x}}{x} + Ei (x) + C

d er i v a t i v e \frac{( ( x + 1 ) ( x + 2 ) )}{x}

x \to - 3 + lim (\frac{- 5 x}{x + 3})

\int_{0}^{1} x 3^{x} d x

2 x d y + y d x = 0

x y y^{^{'}} + 4 x^{2} + y^{2} = 0

What is the integral of e^xx^{-2} ?
The integral of e^xx^{-2} is -(e^x)/x+\Ei(x)+C