What is the derivative of 5/((4x^{-2)}) ?

The derivative of 5/((4x^{-2)}) is 160x

What is the first derivative of 5/((4x^{-2)}) ?

The first derivative of 5/((4x^{-2)}) is 160x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (\frac{5}{( 4 x ) ^{- 2}})

160 x

Solution steps

\frac{d}{d x} (\frac{5}{( 4 x ) ^{- 2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{( 4 x ) ^{- 2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((4 x)^{2})

Apply the chain rule:

2 \cdot 4 x \frac{d}{d x} (4 x)

= 2 \cdot 4 x \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 5 \cdot 2 \cdot 4 x \cdot 4

Simplify

= 160 x

\frac{d}{d x} (cos (wt))

\int_{0}^{\frac{π}{20}} tan (10 x) d x

d er i v a t i v e f (x) = (2 x - 3) \cdot x

\frac{d}{d x} (2 sin (x))

t an g e n t \frac{2}{1 - t}, at t = - 2

What is the derivative of 5/((4x^{-2)}) ?
The derivative of 5/((4x^{-2)}) is 160x
What is the first derivative of 5/((4x^{-2)}) ?
The first derivative of 5/((4x^{-2)}) is 160x