What is the solution for y^2(dy)/(dx)=y^3-x^3 ?

The solution for y^2(dy)/(dx)=y^3-x^3 is y=\sqrt[3]{(9x^3+9x^2+6x+2+9c_{1}e^{3x})/9}

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y^2(dy)/(dx)=y^3-x^3

y^{2} \frac{d y}{d x} = y^{3} - x^{3}

y = 3 \frac{9 x ^{3} + 9 x ^{2} + 6 x + 2 + 9 c _{1} e ^{3 x}}{9}

Solution steps

y^{2} \frac{d y}{d x} = y^{3} - x^{3}

Solve Bernoulli ODE:

y = 3 \frac{9 x ^{3} + 9 x ^{2} + 6 x + 2 + 9 c _{1} e ^{3 x}}{9}

y = 3 \frac{9 x ^{3} + 9 x ^{2} + 6 x + 2 + 9 c _{1} e ^{3 x}}{9}

x \to \frac{π}{2} lim (f (x))

\frac{d}{d x} (tan^{3} (4 x))

t an g e n t f (x) = - 2 x^{3}, (2, - 16)

y^{^{''}} + y^{^{'}} - 2 y = 4 sin (2 x)

\int e^{- 0.89 x} d x

What is the solution for y^2(dy)/(dx)=y^3-x^3 ?
The solution for y^2(dy)/(dx)=y^3-x^3 is y=\sqrt[3]{(9x^3+9x^2+6x+2+9c_{1}e^{3x})/9}