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Popular >

derivative of 4sin(2x-3cos(3x))

Solution

\frac{d}{d x} (4 sin (2 x) - 3 cos (3 x))

Solution

8 cos (2 x) + 9 sin (3 x)

Solution steps

\frac{d}{d x} (4 sin (2 x) - 3 cos (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 sin (2 x)) - \frac{d}{d x} (3 cos (3 x))

\frac{d}{d x} (4 sin (2 x)) = 8 cos (2 x)

\frac{d}{d x} (3 cos (3 x)) = - 9 sin (3 x)

= 8 cos (2 x) - (- 9 sin (3 x))

Simplify

= 8 cos (2 x) + 9 sin (3 x)

Popular Examples

integral from-2 to 0 of-x^2-2x

\int_{- 2}^{0} - x^{2} - 2 x d x

inverse oflaplace 1/(s(s^2+s+1))inverse laplace

\frac{1}{s ( s ^{2} + s + 1 )}

(\partial)/(\partial x)(1/(x^2)c)

\frac{\partial}{\partial x} (\frac{1}{x ^{2}} c)

derivative of f(x)=3x-5 derivative of

f (x) = 3 x - 5

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\int_{- 2}^{2} (6 x) - (x^{2} - 7) d x

Frequently Asked Questions (FAQ)

What is the derivative of 4sin(2x-3cos(3x)) ?
The derivative of 4sin(2x-3cos(3x)) is 8cos(2x)+9sin(3x)
What is the first derivative of 4sin(2x-3cos(3x)) ?
The first derivative of 4sin(2x-3cos(3x)) is 8cos(2x)+9sin(3x)