derivative y=(6x-1)/(8x+3)

Lösung

ableitung von

y = \frac{6 x - 1}{8 x + 3}

\frac{26}{( 8 x + 3 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{6 x - 1}{8 x + 3})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 6 x - 1 ) ( 8 x + 3 ) - \frac{d}{d x} ( 8 x + 3 ) ( 6 x - 1 )}{( 8 x + 3 ) ^{2}}

\frac{d}{d x} (6 x - 1) = 6

\frac{d}{d x} (8 x + 3) = 8

= \frac{6 ( 8 x + 3 ) - 8 ( 6 x - 1 )}{( 8 x + 3 ) ^{2}}

Multipliziere aus

6 (8 x + 3) - 8 (6 x - 1) : 26

= \frac{26}{( 8 x + 3 ) ^{2}}

t a y l or tan^{- 1} (x)

\frac{d}{d x} ((2 - 6 x)^{0.5})

\frac{d}{d x} (0.1 x^{2})

\frac{\partial}{\partial x} (x^{3} + y z^{2})

d er i v a t i v e (x^{2} - 2)^{2}