1/y (dy)/(dx)=e^x+log_{e}(y)

Lösung

\frac{1}{y} \frac{d y}{d x} = e^{x} + lo g_{e} (y)

y = e^{c_{1} e^{x} + x e^{x}}

Schritte zur Lösung

\frac{1}{y} \frac{d y}{d x} = e^{x} + lo g_{e} (y)

Solve exact ODE:

y = e^{c_{1} e^{x} + x e^{x}}

y = e^{c_{1} e^{x} + x e^{x}}

\int \frac{x}{2 1 + x} d x

a re a x = - y, x = 2 - y^{2}

x \to 6 lim (g (x))

\int \frac{1}{x ^{2} 7 - 16 x ^{2}} d x

\frac{\partial}{\partial y} (1 - x^{2} - y^{2})