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Popular Calculus >

derivative of g(t)=t^2-4/(t^3)

Solution

derivative of

g (t) = t^{2} - \frac{4}{t ^{3}}

Solution

2 t + \frac{12}{t ^{4}}

Solution steps

\frac{d}{d t} (t^{2} - \frac{4}{t ^{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{2}) - \frac{d}{d t} (\frac{4}{t ^{3}})

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (\frac{4}{t ^{3}}) = - \frac{12}{t ^{4}}

= 2 t - (- \frac{12}{t ^{4}})

Simplify

= 2 t + \frac{12}{t ^{4}}

Graph

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Frequently Asked Questions (FAQ)

What is the derivative of g(t)=t^2-4/(t^3) ?
The derivative of g(t)=t^2-4/(t^3) is 2t+(12)/(t^4)
What is the first derivative of g(t)=t^2-4/(t^3) ?
The first derivative of g(t)=t^2-4/(t^3) is 2t+(12)/(t^4)