What is the first derivative of 6x-4 ?

The first derivative of 6x-4 is 6

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derivative of 6x-4

derivative of

6 x - 4

6

Solution steps

\frac{d}{d x} (6 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x) - \frac{d}{d x} (4)

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (4) = 0

= 6 - 0

Simplify

= 6

\int (tan (x) - cot (x))^{2} d x

s l o p e (x - 3)^{2} + (y - 1)^{2} = 0

d er i v a t i v e y = arcsin (4 x + 1)

a re a y = 2 sin (x), 0 \leq x \leq π

\frac{d y}{d x} = (y - 1)^{2} cos (π x)