What is the solution for (dy)/(dx)=((1-y))/(1+x^2) ?

The solution for (dy)/(dx)=((1-y))/(1+x^2) is y=-e^{-arctan(x)-c_{1}}+1

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(dy)/(dx)=((1-y))/(1+x^2)

\frac{d y}{d x} = \frac{( 1 - y )}{1 + x ^{2}}

y = - e^{- a r c t a n (x) - c_{1}} + 1

Solution steps

\frac{d y}{d x} = \frac{( 1 - y )}{1 + x ^{2}}

Solve separable ODE:

y = - e^{- a r c t a n (x) - c_{1}} + 1

y = - e^{- a r c t a n (x) - c_{1}} + 1

\int_{2}^{\infty} \frac{1}{4 + x ^{2}} d x

\int \frac{x ^{2} + x + 1}{( x ^{4} + 2 x ^{2} + 1 ) ^{2}} d x

\int \frac{x ^{3} + 3 x ^{2} + 4}{4 x ^{2} + 2} d x

d er i v a t i v e f (x) = 2 x^{4} + 3 x + 16

\frac{d}{d t} (\frac{6}{5} - \frac{6}{5} e^{- 20 t})

What is the solution for (dy)/(dx)=((1-y))/(1+x^2) ?
The solution for (dy)/(dx)=((1-y))/(1+x^2) is y=-e^{-arctan(x)-c_{1}}+1