derivative f(x)=9x+4x^{-1}

解答

导数

f (x) = 9 x + 4 x^{- 1}

9 - \frac{4}{x ^{2}}

求解步骤

\frac{d}{d x} (9 x + 4 x^{- 1})

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x) + \frac{d}{d x} (4 x^{- 1})

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (4 x^{- 1}) = - \frac{4}{x ^{2}}

= 9 - \frac{4}{x ^{2}}

a re a y = 4 x, y = 6 x^{2}

y^{^{''}} + 2 y^{^{'}} + 4 y = 0, y (0) = 1, y^{^{'}} (0) = 0

\int t sin (t) d t

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