What is the tangent of f(x)=-2sin(x),\at x= 3/4 pi ?

The tangent of f(x)=-2sin(x),\at x= 3/4 pi is y=sqrt(2)x-sqrt(2)-(3pi)/(2sqrt(2))

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tangent of f(x)=-2sin(x),\at x= 3/4 pi

tangent of

f (x) = - 2 sin (x), at x = \frac{3}{4} π

y = 2 x - 2 - \frac{3 π}{2 2}

Solution steps

Find the tangent point:

(\frac{3}{4} π, - 2)

Find the slope of

f (x) = - 2 sin (x) : \frac{df ( x )}{d x} = - 2 cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(\frac{3}{4} π, - 2) : y = 2 x - 2 - \frac{3 π}{2 2}

y = 2 x - 2 - \frac{3 π}{2 2}

\frac{d}{d x} (\frac{1}{arccos ( x ^{2} + 2 x + 4 )})

\int 0 e^{x} d x

\int 6 e^{- 5 x} d x

t an g e n t f (x) = 1 - x^{2}, at x = 2

\int \frac{21}{25 + 4 r ^{2}} d r

What is the tangent of f(x)=-2sin(x),\at x= 3/4 pi ?
The tangent of f(x)=-2sin(x),\at x= 3/4 pi is y=sqrt(2)x-sqrt(2)-(3pi)/(2sqrt(2))