What is the d/(dy)(1/(y^2)) ?

The d/(dy)(1/(y^2)) is -2/(y^3)

What is the first d/(dy)(1/(y^2)) ?

The first d/(dy)(1/(y^2)) is -2/(y^3)

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\frac{d}{d y} (\frac{1}{y ^{2}})

- \frac{2}{y ^{3}}

Solution steps

\frac{d}{d y} (\frac{1}{y ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d y} (y^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 y^{- 2 - 1}

Simplify

- 2 y^{- 2 - 1} : - \frac{2}{y ^{3}}

= - \frac{2}{y ^{3}}

x \to 2 lim (h (x))

\frac{d y}{d x} - 2 x y = - 3 x^{2} e^{x^{2}}

y \to 5 lim (\frac{25 - y ^{2}}{y ^{2} - 4 y - 5})

\int \frac{sin ( 2 t + 1 )}{cos ^{2} ( 2 t + 1 )} d t

y^{^{'}} = \frac{1 - x}{y}