What is the derivative of (1+x^2^3) ?

The derivative of (1+x^2^3) is 6x(1+x^2)^2

What is the first derivative of (1+x^2^3) ?

The first derivative of (1+x^2^3) is 6x(1+x^2)^2

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\frac{d}{d x} ((1 + x^{2})^{3})

6 x (1 + x^{2})^{2}

Solution steps

\frac{d}{d x} ((1 + x^{2})^{3})

Apply the chain rule:

3 (1 + x^{2})^{2} \frac{d}{d x} (1 + x^{2})

= 3 (1 + x^{2})^{2} \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= 3 (1 + x^{2})^{2} \cdot 2 x

Simplify

= 6 x (1 + x^{2})^{2}

\int 15.7 - 0.2 x d x

\int_{4}^{9} 3 x d x

\int 3 x^{3} cos (x) d x

t an g e n t f (x) = x^{2} - 5 x + 5, at x = 0

x \to 9 lim (x)

What is the derivative of (1+x^2^3) ?
The derivative of (1+x^2^3) is 6x(1+x^2)^2
What is the first derivative of (1+x^2^3) ?
The first derivative of (1+x^2^3) is 6x(1+x^2)^2