f^'(x)=2x+3x^{1.7}

解答

f^{^{'}} (x) = 2 x + 3 x^{1.7}

f (x) = x^{2} + 1.11111 \dots x^{2.7} + c_{1}

求解步骤

f^{'} (x) = 2 x + 3 x^{1.7}

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

f (x) = \int 2 x + 3 x^{1.7} d x

\int 2 x + 3 x^{1.7} d x = x^{2} + 1.11111 \dots x^{2.7} + c_{1}

f (x) = x^{2} + 1.11111 \dots x^{2.7} + c_{1}

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